(1/4x)^-2=a0/x^2

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Solution for (1/4x)^-2=a0/x^2 equation: 


D( x )

(1/4)*x = 0

x^2 = 0

(1/4)*x = 0

(1/4)*x = 0

1/4*x = 0 // : 1/4

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

((1/4)*x)^-2 = (a^0)/(x^2) // - (a^0)/(x^2)

((1/4)*x)^-2-((a^0)/(x^2)) = 0

((1/4)*x)^-2-x^-2 = 0

15*x^-2 = 0 // : 15

x^-2 = 0

x należy do O

x belongs to the empty set

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